F(x)=21(12x^2+2)+10

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Solution for F(x)=21(12x^2+2)+10 equation: 



(F)=21(12F^2+2)+10

We move all terms to the left:

(F)-(21(12F^2+2)+10)=0



We calculate terms in parentheses: -(21(12F^2+2)+10), so:

21(12F^2+2)+10

We multiply parentheses

252F^2+42+10

We add all the numbers together, and all the variables

252F^2+52

Back to the equation:

-(252F^2+52)



We get rid of parentheses

-252F^2+F-52=0

a = -252; b = 1; c = -52;
Δ = b2-4ac
Δ = 12-4·(-252)·(-52)
Δ = -52415
Delta is less than zero, so there is no solution for the equation

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